25c^2+15c=0

Solution for 25c^2+15c=0 equation:

25c^2+15c=0

a = 25; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·25·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*25}=\frac{-30}{50}
=-3/5
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*25}=\frac{0}{50}
=0
$